经过回代后可得 b (3) 0.68513854 二 (3) =0.36725739 0.18655541×10 33 x305-018015×10 x =-0.05088607 0.3176×10 22 2 X =-0.49105820 事实上,方程组的准确解为 x*=(-0.4910582270.0508860750.367257384)(3) (3) 3 3 33 a b x = = 经过回代后可得 (1) 11 3 (1) 2 13 (1) 12 (1) 1 1 a b a x a x x - - = 0.685 138 54 0.186 555 41´10 = 0.367 257 39 (2) 22 3 (2) 23 (2) 2 2 a b a x x - = 0.3176 10 0.5 0.18015 10 3 ´ - ´ ´ = x = -0.05088607 = -0.49105820 事实上,方程组的准确解为 T x* = (-0.491058227,-0.050886075,0.367257384)