O 1+J OL OC O RO O →N(jo)= =A()∠(O) A() o 0 Q=0667 幅频特性 O=1.67 A(@ 1+0 Q=5 O Q=10 0|0.5幅频特性 1 ( ) 1 1 1 N j j L R C = + − 0 0 0 0 0 1 1 L j L j jQ R C R − = − = − 0 0 1 ( ) ( ) ( ) 1 N j A jQ = = + − 2 2 0 0 1 ( ) 1 A Q = + − A( ) 1 1 20 0.5 0 1.5 2 Q = 0.667 Q =1.67 Q = 5Q =10