2、用行列式波函数计算能量期待值 E=(v(1)2(2)-v2(1)1(2)h(1)+h(2)+W(2(2)-v2(1(2 2 ×e++1)2(22+ 2(e;++)-2×0+0+(w02(2)420w(2) 2 2 e=alta tJ Is 2s K Iss2、用行列式波函数计算能量期待值： (1) (2) (1) (2) 1 (2) ˆ (1) ˆ (1) (2) (1) (2) 2 1 1 2 2 1 12 = 1  2 − 2 1 + +   −  r E h h =   + + −  (1) (1) (2) (2) + ˆ 2 ( ) 2 (1) 2 1 1 2 1 2 2 1 0 2 0  1s  s J s s  h            + (1) (2) 1 (2) (2) (1) (2) ˆ (1) (1) (2) 2 1 1 2 1  2  2 1 1  2   r h ( )                 =  + + −  + + (1) (2) 1 2 2 0 0 (1) (2) 2 1 2 1 1 2 1 2 1 2 0 2 0  1      r J s s s s s s s s K s s E J1 2 1 2 0 2 0 =  1 + + −