这个电磁场满足的边界条件如何?电壁上的电流密度值如何? x=0 a E.=0→ sin(kz-otsin -=0 x=aj →>E、=H =0 a H.=0→ - H H sin sin(kz-at)=0 x三a a X=0J=n×H e. X ehteR X HzL=-e, Ho COS(k-or Xa n×H e×e h teh X e, Ho COS (kz-at) X=a这个电磁场满足的边界条件如何?电壁上的电流密度值如何? ( ) ( ) t y 0 n X 0 0 a x E 0 E =H sin kz- t sin =0 a 0 a x H 0 H =-H k sin sin kz- t =0 a x x a x x a = = → → = = = → → = ( ) ( ) ( ) x y 0 0 x y x=0 =e = -e x=a =-e = e S x X Z Z Z y x S x X Z Z Z x J n H e H e H H e H COS kz t J n H e H e H H = = + = − − = + y 0 ( ) a e H COS kz t = = − −