将F(s)= costU(t)5s +/12(0)=1y(0)=1代入方程 s+4 2 5s Y(S) s2+5s+6s2+5s+6s2+1 s+4 10 Y(S) (S+2)(s+3)(s+2)S+3)s+j)(S-j) Y(s)=(+ s+2s+3s+2s+2s+ y()={[(2e2-e3)+[-4e cos(t-10(t)将 , y(0 ) 1, y (0 ) - 1代入方程 s 1 5s F(s) L[5costU(t)] - ' 2 - = = + = = (s 2)(s 3)(s )( ) 10s (s 2)( 3) s 4 Y(s) s + + + j s − j + + + + = s 1 5s s 5s 6 2 s 5s 6 s 4 Y(s) 2 2 2 + • + + + + + + = )]} ( ) 4 ( ) {[(2 ) [ 4 3 2 cos( 2 1 2 1 2 3 2 4 ) 3 1 2 2 ( ) ( 2 3 2 3 4 4 y t e e e e t U t s j e s j e s s s s Y s t t t t j j    = − + − + + −             − + + + + + + − + + − + + = − − − − −