例2求函数y=f"p"(sinx")的导数 解y'=uf"p"(sinx")·f'o"(sinx")l np" (sin x")p(sinx")·cosx"·nx n-1 =n3:x"-cosx"·∫"|o"(sinx") q"(sinx")·fIp"(sinx")·q(sinx") 上页例 2 求函数 [ (sin )]的导数. n n n y = f  x 解 [ (sin )] [ (sin )] n 1 n n n n y = nf  x  f   x − (sin ) (sin ) n 1 n n  n x   x − 1 cos −   n n x nx (sin ) [ (sin )] (sin ). cos [ (sin )] 13 1 1 n n n n n n n n n n x f x x n x x f x       =     − − −