Continue Example 38.1 Steam Solution: T1=400C P=30 bars ·From steam tables: h1=3230.9kJ/kg s=6.9212kJ/kg·K) h2=2716.6kJ/kg s2=7.4668kJ/(kg·K) T2=120C p2=1 bar 1st law,energy balance: --++差 dt W=minhin-mouhout Mass balaee:i=m。=i w,=h-h,=(3230.9-2716.6)=5143 g 上游通大学 April 30,2019 9 SHANGHAI JIAO TONG UNIVERSITYApril 30, 2019 9 Continue Example 38.1 Solution: • From steam tables: • 1 st law, energy balance: CV dE dt 2 in v Q W m h 2      gz 2 out out in v m h 2             gz   out in in out in in out out T 1 2 Mass balance : m m m W m h m h kJ kJ w h h 3230.9 2716.6 514.3 kg kg                   1 1 2 2 h 3230.9 kJ kg s 6.9212 kJ (kg K) h 2716.6 kJ kg s 7.4668 kJ (kg K)       . WT CV Steam T1=400oC p1=30 bars T2=120oC p2=1 bar