[Z2[×;,是Z2上的多项式环。取p(x)= x2+x+1则zx](p(x)={p(x),(p(x)+1 (p(x)+x,(p(x)+(x+1)简化为{0,1,x,x+1} x+1 ⊕01x 001x X+1 0 x+1 x+1 0 x+1 X+1 x+1 01x 0000 0 0 x+1 x+1 x+1 X+1▪ [Z2 [x];+,*]是Z2上的多项式环。取p(x)= x 2+x+1,则:Z2 [x]/(p(x))={(p(x)), (p(x))+1, (p(x))+x,(p(x))+(x+1)},简化为{0,1,x,x+1}  0 1 x x+1 0 0 1 x x+1 1 1 0 x+1 x x x x+1 0 1 x+1 x+1 x 1 0  0 1 x x+1 0 0 0 0 0 1 0 1 x x+1 x 0 x x+1 1 x+1 0 x+1 1 x