√M<0.3 tanh≈√M E≈1 y (3-107) +kcc +kcc N,=K°c1+2ca (3-110) bD,c D.C < N=K BCE NA=EK∠CA (3-113) E= [M(E2-E)∥E2-ly tanh(E,/] (3-114) Msk,CBL(对二级反应) k2) (3-115) E=1 DBCBL bD A Ai √M>10E d,kM  1 M  0.3 tanh M  M cosh M 1 E  1 A bB P + ⎯⎯k2→ A A B B b A  = k c c ;  =  2 (3-107) A B A A A k c c c Z c D 2 2 2 +   =    (3-108) A B B B B k c c c Z c D 2 2 2 +   =    (3-109)         = + A Ai B BL A L Ai bD c D c N K c 1 0 (3-110) A Ai B BL bD C D C E = 1+ (3-111) Ai BL c  c A B BL A L bD D c N K 0 = (3-112) A L Ai N EK c 0 = (3-113)  ( )   ( )  2 1 2 1 1 1 − − − − =     tanh M E E E M E E E E (3-114) ( ) (对二级反应) 2 0 L A 2 BL k D k c M = (3-115) A Ai B BL bD c D c E = 1+ (3-116) M  10E          + A Ai B BL A 2 BL L bD c D c D k c 10k 1 0 (3-117)