ac, a-c D +D dz+ydz DaC=aC y=ki k (3-101) sinh Z D simh√M D D N D C n=k cOs√MmM M≥1 tah√M≈1 N Dk (3-105) na=K E=k2/k=VD/k=√MdZ dZ c dZ Z c Z c D Z c D A A 2 A 2 A A A A   +   =           +    +        − A A 2 A 2 A c Z c D   +   =   (3-99) A P ⎯⎯k1→ A A k c = 1  A A 2 A 2 A k c c Z c D + 1   =    (3-100) = 0    A c 2 A A 2 A k c Z c D = 1   (3-101) 0 , ; , A A i A A L Z = c = c Z =  L c = c                 = + − L A A Ai A A AL D k Z k D c sinh D k c sinh Z sinh M c 1 0 1 1 (3-102) =0         = − Z A A A Z c N D (3-103) tanh M M cosh M c N k c AL A L Ai       = − 0 (3-104) M  1 M  3 tanh M 1 cAL = 0 1 N c D k A = Ai A (3-105) Ai NA K c 0 = L E k k D k k M 0 A L 0 = L L = 1 = (3-106)