G和G,同构吗？ We can define an isomorphism from G to G by gAg.The group operation is preserved since (gh)=入gh=入g入h=(g)(h) It is also one-to-one,because if o(g)(a)=o(h)(a),then ga=入ga=入ha=ha. Hence,g=h.ThatΦis onto follows from the fact that(g)=λg for any Ag∈G. ▣𝐺和𝐺ҧ，同构吗？