正旋电磁场的复数表示 ·例2将下列场矢量的复数形式写为瞬时值形式 (1)E=a.Eo sin(kx)sin(ky)e (2)=dj2Esincos(k,cos0)ein ·解] (1)E=Re[Ee/]=a.Eo sin(k x)sin(kyy)cos(@t-k.2) (2)E=Re[Ee/W] =dRele2EsinOcos(k,Cos0)e =a,2E sinecos(k,cose)cos(ot-k.zsin+) lexu@mail.xidian.edu.cn =-a,2 sinecos(k,cose)sin(ot-k.zsine)正旋电磁场的复数表示  例2 将下列场矢量的复数形式写为瞬时值形式  [解] lexu@mail.xidian.edu.cn 10 0 sin 0 (1) sin( )sin( ) ˆ (2) 2 sin cos( cos ) ˆ z z jk z z xy jk z x x E aE kx k ye E ajE k e θ θ θ − − = =     0 (1) Re[ ] sin( )sin( )cos( ) ˆ j t E Ee a E k x k y t k z z xy z ω = = ω −   sin 2 0 0 0 (2) Re[ ] ˆ Re[ 2 sin cos( cos ) ] ˆ 2 sin cos( cos )cos( sin ) 2 ˆ 2 sin cos( cos )sin( sin ) z j t j jk z j t x x xx z xx z E Ee a eE k e e a E k t kz a E k t kz ω π θ ω θ θ π θ θω θ θ θω θ − = = = − + = − −   XIDIAN UNIVERSITY LEXU@MAIL.XIDIAN.EDU.CN