在拉格朗日参考系中求加速度, (-2ae)=4ae=4x t at [2b(1+)=2b=2y 4cet 2ce 6ce-t 2ce a-t at (1+1)」(1+1)3(1+1)3(1+ 2ce[2(1+)+(1+t)-3]2ce"(2t2+1)2z(2t2+1) (1+1) (1+t)2 2 2 2 ( 2 ) 4 4 t t x x a ae ae x t t − − = = − = = 2 2 2 2 [2 (1 )] 2 (1 ) y y y a b t b t t t = = + = = + 2 2 2 2 2 2 3 3 3 4 4 2 6 2 (1 ) (1 ) (1 ) (1 ) t t t t z z t ce t ce ce t a ce t t t t t t = = = + − + + + + 2 2 2 2 4 4 2 2 [2 (1 ) (1 ) 3 ] 2 (2 1) 2 (2 1) (1 ) (1 ) (1 ) t t ce t t t t ce t z t t t t + + + − + + = = = + + + 在拉格朗日参考系中求加速度