5.3开环系統的伯德图 Bode图绘制 10 10 G(s)= GK(S) (S+1)0.2s+1) S(0.2s+1) A()=10 人(o)2+1√(020)2+1) I()=201g10+20/g~1+2019(020)+1) (c)2+1 P(o=-atan(o-a tan(0. 2o)5.3 开环系统的伯德图 10 ( ) ( 1)(0.2 1) G s k s s = + + 10 ( ) (0.2 1) G s k s s = + 2 2 1 1 ( ) 10 ( ) 1 (0.2 ) 1) A    =   + +     ( ) tan( ) tan(0.2 ) = − − a a 2 2 1 1 ( ) 20lg10 20lg 20lg ( ) 1 (0.2 ) 1) L    = + + + + Bode图绘制