解:①)u2=√3RT/A, PV=MRT∴P7p=RT 2=3P/p =√3×10×102×1.013×10/1.2102 ≈494m/s (2)∵√U2=√3RT/=494m/s =3R(494)2=28×10 kg mol 是N2,CO(1) 3 / , 2 解： v = RT  PV = MRT /  P /  = RT /  3 /  2 v = P 3 1.0 10 1.013 10 /1.24 10 -2 5 -2 =       494m/s (2) 3 /  2  v = RT 3 /(494)2  = RT 28 10 kg mol 3 1 =   - - N ,CO. 是 2 = 494m/s