用结点电压代入后得: kung t(u )2+(un2-un3) k=1 +(unl+un3)i4+unis +un3i6 t ∑ kk n(1+i2-i4)+un2(i2+i3+i) k=1 +u 1,十1A 4 括号内为各结点上电流代数和,因此有: ∑uk=0→∑u=0 k=1 k=1用结点电压代入后得: n1 n3 4 n2 5 n3 6 n1 1 n1 n2 2 n2 n3 3 6 k 1 k k ( u u )i u i u i u i u i (u u )i (u u )i 或: u ( i i i ) u i u (i i i ) u ( i i i ) n3 3 4 6 n1 1 2 4 n2 2 3 5 6 k 1 k k 括号内为各结点上电流代数和,因此有: u i 0 6 k 1 k k u i 0 b k 1 k k