B= s=j0B.5ò） 3+j8 e+82.3”6-2,30 由于变量的任意性，即所有系数为零。寻找s 系数 m=K 5+j6)∑bns"+(5-jδ)∑b -2m5m m=k+1 m=k+1( ) ( ) -2 × + - = - d d d B s s j s j B s n n ( ) ( ) 0 0 2 0 + å + - å = = - = n m m m m n m m m s jd b s s jd b d s 由于变量的任意性，即所有系数为零。寻找 系数 k+1 s ( )å ( )å= - = + + - n m m m m n m m m s j b s s j b s 0 2 0 d d d m = k m = k +1 m = k m = k +1