反应：H2+12==2HⅢ ①L242I ②2I2 ③H2+2I42HⅢ r=kci, n=kc =k; ( dc) dt 当-告当=22-反应： H2+ I2 === 2HI ①I2 → 2I ②2I → I2 ③H2 + 2I → 2HI 2 1 1 I r = k c 2 2 2 I r = k c 1 k 2 k 3 k H2 2 3 3 I r = k c c 1 I 1 I 1 ) d d ( 2 1 ) d d ( 2 t c t c r = − = 2 I 2 I 2 ) d d ( 2 1 ) d d ( 2 t c t c r = = − 3 H I 3 I 3 H 3 ) d d ( 2 1 ) d d ( 2 1 ) d d ( 2 t c t c t c r = − = − = − 2 2 1 I 2 I I 1 I I I 2 2 2 2 2 ) d d ) ( d d ( d d k c k c t c t c t c r = − = − + − = − 2 H2 2 3 I 2 3 1 I 2 I I 2 I 1 I I I ) 2 2 2 d d ) ( d d ) ( d d ( d d k c k c k c c t c t c t c t c r = = + + = − −