于是7在基(a2,a1)下的矩阵为 01/an1a2)∥01 B= 10 2122 10 a21a2Y01 (11 (12 10 2221 = 1211 上页于是T在基(2 ,1 )下的矩阵为                   = 1 0 0 1 1 0 0 1 21 22 11 12 a a a a B . 12 11 22 21      = a a a a             = 1 0 0 1 11 12 21 22 a a a a