2 O2,MO:(a1)2(o1)2(a2,)(023)(2m)1m重m2|2m) p2 =Vm(n+2)BM=1.73BM.1a+2 O2,MO:(o1)(G)(02)(o2)(2x 2py 2 *2(O 2 p2 u=vn(n+2)BM=0 lo 0 2 O2,MO:(o1)(a1)2(a2)(2)2(2p3)2p py 2 px 2 =√m(n+2)BM=1.73BM.1+1n2+1n3 2 0 O2+,MO:(o1)2(o1)(o2)2(o2,)2(2) 2 2 2 =√n(n+2)B.M.=0 10+2兀22/26/2021 7 ＝ ( 2)B.M. 1.73B.M. O , :( ) ( ) ( ) ( ) ( ) ( ) 2 2 2 1 2 2 2 2 2 2 2 2 2 2 2 2 1 2 2 1 + =                    −   n n MO p x p z p y p z p y s s s s p x            ＝ ( 2)B.M. 0 O , :( ) ( ) ( ) ( ) ( ) ( ) 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 2 1 2 2 + =                    −   n n MO p x p z p y p z p y s s s s p x            ＝ ( 2)B.M. 1.73B.M. O , :( ) ( ) ( ) ( ) ( ) ( ) 1 2 2 0 2 2 2 2 2 2 2 2 2 2 2 2 1 2 1 ＋ 2 + =                      n n MO p x p z p y p z p y s s s s p x            ＝ ( 2)B.M. 0 O , :( ) ( ) ( ) ( ) ( ) ( ) 0 2 2 0 2 2 2 2 2 2 2 2 2 2 2 2 1 2 1 2＋ 2 + =                      n n MO p x p z p y p z p y s s s s p x            1 3 2 1＋ 3 2 2 1＋1 2 ＋1 2 1＋2 2