(97.8-2.20)kPa×4.16L n(N2)= =0.164mol 8.314J.K-1.mol-1×292K NHNO2(s)>2H2O(g)+N2(g) 64.04g 1mol m(NHNO2)=? 0.164mol 64.04g×0.164mo1 mm(NHNO3 ) =10.5g 1mol 1616 NH4NO2 (s) ⎯→ 2H2O(g) + N2 (g) 64.04g 1mol m(NH4NO2 )=? 0.164mol 0.164mol 8.314J K mol 292K (97.8 2.20)kPa 4.16L ( ) 2 1 1 =    −  = − − n N 10.5g 1mol 64.04g 0.164mo (N H N O ) 4 3 =  = l m