途径B p1=16X105Pa P外1 p=8X105Pa P外2 P2=1X105Pa Vy=1×10-3m3 8×105Pa 22×10-3m3 1X105Pa2=16×10-3m3 WB1=-P外1△V WB2=-P外2△V =-8X105Pa =-1×105Pa ×(2-1)×10-3m3 ×(16-2)×10-3m3 =-800J =-1400J WB =WBI+WB2 =-2200 J 2B=-WB=2200J p外1 途径 B p1 = 16×105Pa V1= 1×10-3m3 p2 = 1×105Pa V2= 16×10-3m3 p = 8×105Pa V= 2×10-3m3 8×105Pa p外2 1×105Pa WB1 ＝ - p外1 ∆V ＝ -8×105Pa ×(2 – 1)×10-3m3 ＝ -800 J WB ＝WB1 + WB2 = -2200 J WB2 ＝ - p外2 ∆V ＝ -1×105Pa ×(16 – 2)×10-3m3 ＝ -1400 J QB ＝ - WB ＝ 2200 J