(3)若T是非奇异的则 exp(t" AT)=T(exp a)T 由于 exp(T7)=∑ S(TAT k=0 k! =E+X(747) TAT e+ k=1 k ∑ k=1 k k =7+T②∑ k k =7(E+∑ )T=T(exp a)T k! 常系数线性方程组 国上一页国下一页返回帮助常系数线性方程组 (3) , 若 是非奇异的 则 T AT A T ) (exp ) . = -1 -1 exp(T T 由于: AT) = -1 exp(T 1 0 ( ) ! k k T AT k  − =  = + E 1 1 ( ) ! k k T AT k  − =  = + E 1 1 ! k k T A T k  − =  1 T T− = + 1 1 ( ) ! k k A T T k  − =  1 1 ( ) ! k k A T E T k  − = = + = (exp ) . A T -1 T