(例〉0.1 mol/L AgNO滴定0.1mo/L NaCl,计算0=0.1,0.5， 1,1.5时pAg。 c-0-0 解： 0<1 [CI]= 1+0 0=0.1 [CI]= 0.1X1-0.1) =0.082 1+0.1 [Ag]= K23209 =3.9×09 [ci] 0.082 pAg=8.41 0=05 pAg=8.01 0=1 [Ag"]=[CI ]=Ksp pAg2Pkp2949=474 1 0=1.5 [Ag']= ￡9-D_01X15-D=0.02 1+0 1+1.5 pAg=1.70 1.70 0.02 1 1.5 0.1 (1.5 1) 1 ( 1) 1.5 [ ] 0 = = + × − = + − = = + + pAg c Ag Ag θ θ θ 〈例〉0.1 mol/L AgNO3滴定0.1 mol/L NaCl，计算θ = 0.1, 0.5, 1, 1.5时pAg。 9.49 4.74 2 1 2 1 1 [ ] [ ] = = × = = = = + − sp sp pAg pK θ Ag Cl K 0.5 8.01 8.41 3.9 10 0.082 3.2 10 [ ] [ ] 0.082 1 0.1 0.1 (1 0.1) 0.1 [ ] 1 (1 ) 1 [ ] 9 10 0 = = = = × × = = = + × − = = + − < = − − − + − − − pAg pAg Cl K Ag Cl c Cl sp Cl θ θ θ θ 解： θ