例4设x>0,且Imxn=a>0, n→0 求证lim/xn=√ n→0 证任给E>0, lim x=,(对1=√E) 丑N使得当n>N时恒有xn-a<E1 从而有xn-a=2-a:-aE .+va n 故im√xn=√a例 4 lim . 0, lim 0, x a x x a n n n n n = = → → 求证设 且 证 任给 0 , lim x a, n n = → , 1 N n N x − a 使得当 时恒有 n x a x a x a nn n +− 从而有 − = a x a n − a1 = lim x a. n n = → 故 ( ) 1 对 = a