4.5正弦稳态电路的功率 p109 50 3j252 -j152 解二: 5-j15 i,=10∠0°×10+j25+5-j西 =8.77∠(-105.3)A 分流 i2=i3-i,=14.94∠34.5°A S吸=12Z=8.77×(10+j25)=769+j1923VA 52题=12Z2=14.942×(5-j15)=1116-j3348VA S发=is.i,☑,=10×8.77∠(-105.3)10+j25)=1885-j1425VA o o 1 o 2 2 2 2 1 2 1 1 1 2 2 2 5 j15 10 0 8.77 ( 105.3 ) A 10 j25 5 j15 14.94 34.5 A 8.77 (10 j25) 769 j1923 VA 14.94 5 j15) ( 分流 吸 吸 S I I I S I Z S I Z I − = = − + + − = = + = + = − = = − = = * o 1 1 1116 j3348 VA 10 8.77 ( 105.3 )(10 j25)=1885 j142 发 S 5 VA U S I I Z = = − − + − + _ U 10∠0 o A 10 j25 5 -j15 1 I 2 I 解二: 4.5 正弦稳态电路的功率