⑩串紫学 Teaching Plan on Advanced Mathematics 例5求 ar 解:∫1=∫ 1+ arctan -+O 例6求,d +e 解: d x 1+e-e e b=dx-°d e 1+e 1+e (1+e) 十e =x-l(1+e2)+C.Tianjin Polytechnic University Teaching Plan on Advanced Mathematics 求 . 1 2 2 dx a x  + 解： dx a x  + 2 2 1 dx a a x  + = 2 2 2 1 1 1             + =  a x d a a x 2 1 1 1 arctan . 1 C a x a = + 例5 . 1 1 dx e  x + 例6 求 解： dx e  x 1+ 1 dx e e dx x x   + = − 1 (1 ) 1 1 x x d e e dx + + = −   x ln(1 e ) C. x = − + + dx e e e x x x  + + − = 1 1