解二P=1-P(无8)=1-94/104=0.3439 1-19n=Ci ①k=CCC 4×P n-/33 ②k=CCCC,×P=6.216 n/33 3 k=CCCC!CX P=Ah=33 解—k=CCCC P k/16 解二k=C(C-C;) n/331 - 19 4 C12 n = 12 15 18 1 k = C6 C C C 33 16 = = n P k ? 12 14 12 15 1 k = C6 C C C C ①② 33 32 = = n P k 解一 12 12 25 1 k = C6 C C C 解二 ( ) 15 2 10 1 k = C6 C − C 33 16 = = n P k 解二 1 ( 8 ) 1 9 /10 0.3439. 4 4 P = − P 无 = − = ③ 14 15 1 k = C6 C C 33 8 = = n P k