高数课程妥媒血课件 镭理工大理>> = 2 JJ(x2+y2)dxdydz-(x2+y2)dxdya 1 2 11m0=rh=3听 1=m)h1r,rh=2元, D 2 原式/。4 2 π=336 36 Http://www.heut.edu.cn( ) ( ) , 1 2 2 2 2 2 1 2     = + − +  = − x y dxdydz x y dxdydz I I I   =  1 2 8 2 1 D I rdrd r fdz , 3 4 5 =    =  2 2 2 2 2 D I rdrd r fdz , 6 2 5 =  原式I =  3 4 5 −  6 2 5 = 336 .    =    8 2 4 0 2 0 2 2 r d dr r r dz    =    2 2 2 0 2 0 2 2 r d dr r r dz