@杰山季花 Medieal Universit 省级精品课程申报 0,0=p8m0+0.0592gpop[H' =1.29+00592110-y =1.229-0.0592×7 =0.8146V 21.Write out the structure formula for primary cell.Calculate to the standard electromotive force by known number of the standard electrode potentials. (Ag"/Ag)=0.799 6V,(Cu2/Cu)=0.341 9V,[Ag ][Cu2]=0.1 mol-L (注：electromotive force-一电动势) 解：电极反应分别为： 正极Cu2*+2e=Cu代入能斯特方程 只ne=p2e+05921eCu*1=0.3419+052g01=03419-00592+2 =0.3123V) 负极Ag=Ag+e代入能斯特方程 9=p8+0.05921g[Ag=0.7996+0.05921g0.1=0.7996-0.0592 =0.7404V) 电池电动势为：E=0.3123-0.7404=-0.4281V<0 反应逆向发生，电池组成式为： (Cu|Cu2(0.1moL)Il Ag'(0.1mol-L)|Ag(+) 22.A primay cell consists of SHE and a Cu/Cu electrode.Calculate Cu]when E0.25 V. 解：查标准电极电位表知o(Cu2+/C)0.3419V 根Nernst方程式： p=g+0.0s92y1ecu2=0.3419V+0.0296 VlglCu2 该电池的电动势为： E=(Cu2/Cu)-p(SHE) 0.25V=0.3419V+0.0296 Vlg/Cu2-0.000V 解上述方程： [Cu2h=7.86×10-4moL