(3)D(S)有重根p:,含有(s-p)的因式 设含有(s-p1)3的因式 s+s品+ K 求K、K12和K13 K13=(S-Pi)3F(S)s=pI 例： F(s)=_ +2 s+1)3 (s+1)2F(S)= S+2 =KL+K2-+K3 (s+1) (s+1)(s+1)2”(s+1)3 6+I)FS)= S+2 (s+1)2 K13=(s+1)3F(s)s=1=1 K12=?K1=?䇮ਜ਼ᴹ(s-p1 ) 3Ⲵഐᔿ ≲K11ǃK12઼K13 K13 = (S –p1 ) 3 F(S) s=p1 F(S)= S –p1 K11 (S –p1 ) 2 K12 S –pn Kn + + + • • • + (S –p1 ) 3 K13 + S –p2 K2 11 12 13 2 3 K K K =+ + (s +1) (s +1) (s +1) 1 3 K = (s +1) F(s) 13 s=-1 3 s+2 F(s) = (s +1) ֻ˖ 2 2 12 11 s+2 (s +1) F(s) = (s +1) s+2 (s +1)F(s) = (s +1) K = ?K = ? ˄3˅D(S)ᴹ䟽ṩpi ˈਜ਼ᴹ(s-pi ) nⲴഐᔿ