复数的运算 复数的代数运算 ·复数的积商运算 (a1+ib)(a2+ib2)=(a1a2-bb2)+i(a,b2+a2b) (a1+ib1) =9 idztbbatabab2) (a2+ib2) a好+b好 a?+b2 3=re8 32=re8 21221 ==e.) /32=re915e8=r1r5e9- lexu@mail.xidian.edu.cn 矩阵论● 15 复数的运算 复数的代数运算 复数的积商运算 ( ib )( ib ) ( b b ) i( b b ) 1 1 2 2 1 2 1 2 1 2 2 1 a ib a ib a a b b i a b a b 1 1 1 2 1 2 2 1 1 2 ( ) a b a b ) i a ib a a b b 2 2 2 2 2 1 1 2 2 2 2 2 1 2 1 2 2 2 1 1 ) ( ) ( ) a b i a ib a b y 1 1 i z re 2 2 i z re ii i ( ) y 2 z 1 2 z z 1 2 12 ( ) 1 2 1 2 12 ii i z z re re rre 1 2 12 ( ) 1 2 1 2 12 /// ii i z z re re r re x 2 1 z lexu@mail.xidian.edu.cn 矩 阵 论 15 1 2 1 2 12 z z re re r re /// 0