102动静法的应用(102) 例题103 qd (dp) 解 2 A )(O2) yO D g 2 g D R Ra=qa 2up). sin q 100 Ayo D sin gp.dp 4 2 g R, AyO D g gd d 0 ( d ) sin 2 D R q = 2 2 d 1 ( )( ) 2 2 A D A D q g g = = 2 2 d Nd 2 4 R A D F g = = 2 2 d d 4 F D A g = = Rd o qd y d ( d ) 2 d D q 2 2 2 2 FNd FNd 0 sin d 4 2 A D A D g g = = 解: 例题10.3 10.2 动静法的应用(10.2)