例10-1图示电路,in=10A,i2=5c0s(10t),L1=2H,L2=3H M=1H,求两耦合线圈的磁通链。 M yu=Liii=20wb ≌2=L2i=15c0s(10t)Wb 2 1 =Mi=lowb 12=Mi2=5c0s(10t)Wb Y1 =L1i +Mi2=20+ 5cos(10t Wb Y2=Mi+L2i2=[10+15c0s(10)wb例10-1 图示电路，i1=10A，i2=5cos(10t)，L1=2H，L2=3H， M=1H，求两耦合线圈的磁通链。 i1 * * L1 L2 + _ u1 + _ u2 i M 2 11 = L1 i1 =20Wb 22 = L2 i2 =15cos(10t) Wb 21 = Mi1=10Wb 12 = Mi2= 5cos(10t) Wb 1 = L1 i1 +Mi2=[20+ 5cos(10t)] Wb 2 = Mi1 +L2 i2 =[10+ 15cos(10t)] Wb