=(mv)=(mva =√6zkgm/s 方向 g0= 2 1-12 mva v2 0=54°44'= 6 kgm s A mv  B mv  1 2 t t I −   方向 A B mv mv tg = 54 44' o  = 2 2 = ( ) ( ) 2 2 t 1 t 2 mvA mvB I − = − 