补充内容y"+P(x)y+g(x)y=0可观察出 个特解 (1)若P(x)+xQ(x)=0,特解y=x; (2)若1+P(x)+Q(x)=0,特解y=ex; (3)若1-P(x)+Q(x)=0,特解y=e (4)若Q(x)=0 特解y=1 (5若m(m-1)+mxP(x)+x2g(x)=0 特解y=xm (6)若a2+aP(x)+(x)=0特解y=e补充内容 y + P(x) y + Q(x) y = 0 可观察出 一个特解 (1) 若P(x) + xQ(x) = 0, 特解 y = x; (2) 若1+ P(x) + Q(x) = 0, ; x 特解 y = e (3) 若1− P(x) + Q(x) = 0, . x y e − 特解 = (4)若Q(x) = 0 特解 y = 1 (5) ( 1) ( ) ( ) 0 2 若m m − + mxP x + x Q x = 特解 y = x m (6) ( ) ( ) 0 2 若 +P x + Q x = x y e  特解 =