0.5 -0.8660 0 4q0= 5π/3 -0.0001 q2)= 1.4910 0 -1.0 0 6.1488 8=0.0001 Since s=)is the generalized coordinate vector for0(1) 1 (1) 1 (1) (1) 1 (1) 2 (1) 2 (1) 2 0 0 0 0.0001 0 0 x y x y q (2) (1) (1) 1 1 1 (2) (1) (1) 1 1 1 (2) (1) (1) (2) 1 1 1 (2) (1) (1) 2 2 2 (2) (1) (1) 2 2 2 (2) (1) (1) 2 2 2 0.5 0.8660 5 / 3 1.4910 1.0 6.1488 x x x y y y x x x y y y q Since (1) q (2) q q is the generalized coordinate vector for t = 0 0.0001