性质4设2，乙是A的2个不同特征值， ,P是对应于2，乙，的特征向量，则C,P,线性无关。 证设有一组数k,k2,kP+kB=0(①) 两边左乘A,A(kB+kD)=0=kAP+kB ①)乘2：kP+kB=0→kD(2-2)=0 又2≠元→k=0→k=0 结论设21，乙2，…，1n是方阵的m个特征值，P,P2: …,pn依次是与之对应的特征向量.如果1,2，…，m 各不相等，则P1,P2,…,Pm线性无关 ed by trial v of Print2Flash This document is produced by trial version of Print2Flash. Visit www.print2flash.com for more information