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求解 x (m) J(4)=c(4-) P(m)=∫p(x)ax d(2)=[p(y)h e q(y)= -2 2丌o 2丌 z=1 J(1)= (-2) d(-p) 求使()最小 求解 0 dz (-z) op(z) d(x)-(2-2)d(z)=0 ()=-(2)几 ro(y)dy -z=Φ(z)/q(z) p(y) z)=-z 2丌 F(z=o(z)/(z) \ ] f V [ P O f \ ] f