公式法化简—消图子法 利用A+AB=A+B Y1=ABCD+(A'BC) D+(ABC)=A+B+C+D Y2=A+A"CD+A·Bc =A+A(CD+ Bc)=A+c d+B'C Y3=AC+AD+C. =A'C+(A+CDE C+(A.=A C+D公式法化简——消因子法 利用 A + A’·B = A + B Y1 = A·B’·C’·D + (A·B’·C’)’ = D + (A·B’·C’)’ Y2 = A + A’·C·D + A’·B·C’ = A + A’·(C·D + B·C’) = A + C·D + B·C’ Y3 = A·C + A’·D + C’·D = A·C + (A’+C’)·D = A·C + (A·C)’·D = A·C + D = A’+B+C+D