解:按层叠图依次取各单跨梁计算 ∑MA=0F×4+(10-5×V2×2/2)×6+20=0 125kN(J) 10kN/ ∑Mc=0FA×4-20F=0 G +(5×V2×V2/2-10)×2 Fy=10kN FLy=10kN =0 FAy=7.5kN(↑) ∑F=0 FDx=0 D FRy=10kN F八+5××12120F5=10N E F FAr-5kN() FEy=20kN 52 KN 20KN- m 1 FAx=-5KN 1. FDy=10kN A B C D FAy=7.5kN Fcy=-12.5kN解：按层叠图依次取各单跨梁计算 ∑MA=0 FCy×4+(10－5×√2×√2/2)×6+20=0 FCy =－12.5kN (↓) ∑MC =０ FAy×4－20 +(5×√2×√2/2－10)×2 =0 FAy=7.5 kN (↑) ∑Fx= 0 FAx+5×√2×√2/2=0 FAx =－5kN (←)