Characteristics 2 c(0=a1-e7) c)4 Sope-÷ c(t)1-evr)a 0.632a =Tc(t)=63.2% 茶 866.66 T Practical mathod to estimate T 2T 3T 4T 5T7 Settling time调整时间 t=3Tc(t)=95%· →“5%error zone'”t,=3T t仁4Tc(t)=98.2%→2%error zone'”t,=4T1 ( ) (1 ) t T ct a e    (t0) Characteristics 2 t=T c(t)=63.2% t=3T c(t)=95%  “5% error zone” ts=3T t=4T c(t)=98.2%  “2% error zone” ts=4T Practical mathod to estimate T Settling time 调整时间