AHP=2S(NOClo）-S°(Ca)-2S(NOa） =2(263.3)-223.0-2(210.7) =-117.8JK-mor (c)[4 marks]Calculate AG at 25C AGO AHO-TASO =-75400Jmor1-(25+273K(-117.8 JK-'mol') =-40296JK-mo =-40.3kJmo (d)[4 marks]Calculate the value of Kp at 50C e 40300Jmo1 =ex08314JKm0r50+273K =exp(15.0) =3.29×10 (e)[4 marks]Calculate K at 50C K。=K.RT)” =3.29×10(8.314JK-mor'(50+273)K)- =1225 C3.(a)Use VSEPR theory to predict the shapes of (i)[5 marks]PCl" 5+(4 x 7)-1=32 electrons) −1 0 0 0 0 (g) 2(g) (g) 1 1 H 2S (NOCl ) S (Cl ) 2S (NO 2(263.3) 223.0 2(210.7) 117.8JK mol − − Δ= − − = −− = − (c) [4 marks] Calculate ΔGo at 25o C 00 0 1 1 1 1 1 G H TS 75400Jmol (25 273)K( 117.8JK mol ) 40296JK mol 40.3kJmol − − − − − Δ =Δ − Δ = − − + − = − = − (d) [4 marks] Calculate the value of Kp at 50o C 0 p 1 1 1 6 G K exp RT 40300Jmol exp 8.314JK mol (50 273)K exp(15.0) 3.29 10 − − − ⎛ ⎞ −Δ = ⎜ ⎟ ⎝ ⎠ ⎛ ⎞ = ⎜ ⎟ ⎝ ⎠ + = = × (e) [4 marks] Calculate Kc at 50o C n p c 6 11 K K (RT) 3.29 10 (8.314JK mol (50 273)K) 1225 Δ − − − = = × + = 1 C3. (a) Use VSEPR theory to predict the shapes of (i) [5 marks] PCl4 + 5 + (4 x 7) – 1 = 32 electrons