机械能守恒定律的应用 重物 71=72=0 V1=012)=-W(h+△) 设梁为一线性弹簧,刚度糸数为k 2(k)=k△2 B 7+1=12+12 112mnAF=1 k△ △d △a) 2 2h A-2A△4-2△h=04a=△(1+11+)F1=Fx2u=W(+1+ 2h f=2W Fa=kdF k=1+11+ =K、△4=KA机械能守恒定律的应用： W h Fd d B A T1 = T2 = 0 V1 = 0 ( ) ( ) V2 W = −W h + d 重物 设梁为一线性弹簧,刚度系数为k. ( ) 2 2 2 1 d V k = k T1 +V1 =T2 +V2 ( ) 0 2 1 d 2 kd −W h +  = 2 2 0 s d s 2 d −   −  h = ) 2 (1 1 s d s   =  + + h ) 2 (1 1 s s d d s  = + +   =  h F F W Fd = 2W Fd = Kd Fs s d 2 1 1  = + + h k  d = Kd  s d = Kd s d d F = k s s F = k