§3势垒穿透 梯形势 E(<V) 0 x<0 (x)= 0,x≥0 X 2me x<0:W1(x)+k2v1(x)=0k2 v1=Asin(kx+q)(E>V=0,振动解) x≥0:v2(x)-k2v2(x)=0k2= 2m(0-E) 2=Ce 2 +Dekx D=0 ,=Ce k2- (E<V=V,衰减解)一．梯形势        = , 0 0, 0 ( ) 0 V x x V x 2 2 0 2 2 ( )  m V E k − 0 : 2 0 = 2 2 − 2 =  x   ( x ) k  ( x ) 2 2 1 2  mE 0 : 0 k = 1 2 1 + 1 =  x   ( x ) k  ( x ) §3 势垒穿透 V =V0 ( ) E0 V0 x V 0  = Asin( kx+ ) 1 k x k x Ce De 2 2 2 = + −  D = 0 k x Ce 2 2 −  = (EV＝0, 振动解） （EV＝V0,衰减解）