D 例1:分析下图给定的组合电路。 解:B=ABC A P& B=A·B=A·ABC P=B·R=B·ABC P4=C·R=C·ABC F=P+P+P=AABC+B·ABC+C·ABC 化简: F=ABC(A+B+C) =ABC+A+B+C &解: P1 = ABC P2 = A P1 = A ABC P3 = B P1 = B ABC P4 = C P1 = C ABC F = P2 + P3 + P4 = A ABC + B ABC +C ABC •化简: ABC A B C F ABC A B C = + + + = ( + + ) 1 A C B A C F P1 P2 P3 P4 B & & & & 例1:分析下图给定的组合电路。 & 1 A C B 1 F