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解:1.先求uC(0):画t=0等效电路 30 uC(0) 10=6V 309 20+30 u 10V uc(04)=uc(0)=6V 2.再求i(04),i2(0+):画t=0等效电路 10-6 20220+ 0.2A u(0+) 20 309 10V 6V 0)=0 t=02. 再求 i1 (0+ ) , i2 (0+ ) : 0.2A 20 10 6 i (0 ) 1 = − + = i (0 ) 0 2 + = 10V 20 30 i1 (0+ ) i2 (0+ ) + _ uC(0+ ) = 6V t = 0+ 画t = 0+等效电路 解:1. 先求 uC (0− ): 10 6V 20 30 30 u (0 ) C  = + − = uC (0+ ) = uC (0− ) = 6V 画t = 0−等效电路 10V 20 30 + _ uC(0− ) t = 0-
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