例计算图示结构的等效结点荷载 2(4,5,6) q4 l/2 q (7.9)1 qE2 1,2,3) l/2F=P/2 2l2 P/8 P|/8 q12/12a=90 E O10 [] 10O E o 0 1 =P2 l/2 E丿2 q}2/2 2/12 E几2 P/2 Pl/ 8例.计算图示结构的等效结点荷载 2(4,5,6) 1(1,2,3) 3 (7,8,9) 1 2 P q l l / 2 l / 2 − = − = − /8 / 2 0 1 1 1 1 Pl P Fq P T E = − /8 / 2 0 1 2 Pl PE P = PE 1 E 1 P 1 PE 2 2 E 1 P 2 E 2 + P 2 /12 2 ql ql / 2 q /12 2 ql ql / 2 = 1 2 1 1 1 q q q F F F = /8 / 2 0 1 1 Pl Fq P − = /8 / 2 0 1 2 Pl Fq P = 90 = − 0 0 1 1 0 0 0 1 0 2 − = − = /12 0 / 2 2 2 1 2 1 ql ql P Fq T E = /12 0 / 2 2 2 2 ql ql PE