「a=2,1=-i sin xdx=1 2m-12m-3531π 于是I2mn=-2m 2n-26422 2m2m-2642 2m+/ 2m+12m-1753, 2 2 0 0  =  =  I dx sin 1, 2 0 1 = =   I xdx 于是 , 2 2 1 4 3 6 5 2 2 2 3 2 2 1 2      − −  − =  m m m m I m . 3 2 5 4 7 6 2 1 2 2 2 1 2 2 1     − −  + + =  m m m m I m