先解得: c少∞ p, 3p P P=Cμ P, (n>c) 再由∑P=1解出P,得 (Cp 1 )"P n<c C!C u先解得: 1 0 2 1 3 2 2 3 P P P P P P = = = , , , 1 0 n 1 1 ( ) ! C P P P P P n C C C n C C C = = = − − , ( ) 0 0 1 1 0 0 0 0 1 , ( ) 1 ( ) 1 ! 1 ! 1 ( ) ! 1 ( ) ! n n C n C n n n n n C P P C C P C n C P n C n P P n C C C = − − = − = = + = − = 再由 解出 得: , ,